CS 601-Assignment 1
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| CS 601-Assignment 1 |
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Question 1 (a) |
Solution:
To calculate the transmission time of a packet, you can use the formula:
Transmission Time = Packet Size / Bandwidth
Packet Size = 1 MB = 8 Mb
Bandwidth = 200 Kbps
Transmission Time = 8 Mb / 200 Kbps
Converting kilobits to megabits:
Transmission Time = 8 Mb / 0.2 Mbps
Transmission Time = 40 seconds
So, the transmission time of the packet would still be 40 seconds.
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Question 1 (b) |
Solution:
Download Time = File Size / Bandwidth
Let's calculate the download time:
File Size = 2 MB = 16 Mb
Bandwidth = 1 Mbps
Download Time = 16 Mb / 1 Mbps
Download Time = 16 seconds
Therefore, it would take 16 seconds to download the 2 MB file using a 1 Mbps channel.
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Question 1 (c) |
Solution:
Transmission Time = Frame Size / Bandwidth
Frame Size = 100,000 bits
Bandwidth = 5 Kbps
Transmission Time = 100,000 bits / 5 Kbps
Converting kilobits to bits:
Transmission Time = 100,000 bits / 5,000 bps
Transmission Time = 20 seconds
Therefore, it would take 20 seconds to send a frame of 100,000 bits over a channel with a bandwidth of 5 Kbps.
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Question 2 |
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